BQM39
Here is an elementary life and death problem presented in Kageyama's Lessons in the fundamentals of Go. I was wondering about an alternate solution I think I found. Here it is:
If not, Black can take the group of three and the best White can do seems to be a dead shape of square four, or maybe bent three.
This is the given solution, resulting in a dead bent four in the corner.
Can anyone give me a pointer on whether I'm right or not with my alternate solution?
Bill Spight: Interesting idea! :-)
However:
If Black 5 at 6, White 6 at 5 lives.
Bleahdom?: The original solution gives a bent four in the corner which requires a ko to kill anyway. So I don't quite understand why would this situation be any different?
unkx80: By Japanese rules, bent four in the corner is dead. See that page for details.
Bill: And by area rules it is almost always dead.
Thanks for the quick reply -- my brother, to whom I give a few stones when playing, pointed out that it'd end with a ko if I went for the three stones. I worked out the 5 at 6 idea after that. It felt like a nice move though :) --Splice