Here I present a solution, which I attempt to make as simple as possible, as well as involving the smallest area on the go board as possible. There are other possible variations, please see /Discussion. --unkx80
There is death in the hane. Black reduces White's eye space twice, and then makes the nakade (placement) inside, reducing White to one eye. If White captures at and , Black can answer at and and White has no way out.
Note: can be played at a instead. Likewise, can be played at b instead.
is tricky. is one way, but there are other possible answers. When captures, Black can actually defend at as White has not enough eye space.
In the Solution diagram, when captures a stone, Black should refrain from playing the atari at . It gives a possibility to open up a ko. If Black tries to avoid the ko with onwards, eventually he is caught in a net by and still has to fight the ko.
Eaglehelm: I think this works, so the above diagram would be incorrect.
fractic: No this doesn't work. White can make an eye with and then Black can't prevent her from capturing to make a second eye.