If White plays first, White can save some, but not all, of his stones.
If Black plays first, all White stones will be dead.
Although and can capture five Black stones, all White stones are dead after captures the leftmost chain, because capturing the five-stone Black chain at a gives White only one eye.
If at , then the result is essentially a reversion to the previous diagram.
If Black plays first, the self-atari of is the only move to kill all White stones. has no other choice than to capture the three Black stones.
If proceeds to capture the five Black stones, then captures the leftmost White chain. After , White has only one eye.
saves the leftmost White chain, but is an atari, allowing to capture the three White stones in a ladder and saving the five-stones Black chain.
Seeing the failures of at a or b, now tries to increase the number of liberties of the three-stone chain by pressing here. However, after , and reduces White to only one liberty.
does not work either; after White cannot cut off the two Black stones due to shortage of liberties.