This problem is half a joke in itself, but it is still a real problem! Anyway, it is never a good idea to send four B2 bombers in a collision course!
A simple analysis to make is that if we add the four stones, then the shape becomes a crossed five, with a being the vital point.
So makes a play on the point of symmetry. If is played anywhere else, White at kills.
Later, and are miai, and and are miai.
And and are miai as well. So all the B2 bombers are saved!