The placement at is a vital point, making miai of a and b, therefore White is guaranteed to capture either the single Black stone at the left side or the two Black stone on the right side.
It should be obvious that if White gets to play first, either White at a or b kills. However, if Black first, Black still can save his main group. However, the asymmetry in this problem is an important feature.
If Black plays first, the solution is to connect on the right side with , and then descend with
. Should
destroys the eye at the bottom,
captures the two White stone chain including
.
Connecting at the left side results in failure, because the extra exchange of and
actually decreased Black's liberties, rendering
ineffective. It is also not possible for
to try to live by under the stones technique by playing at a, because
at
is sufficient to kill.