The solution is the snapback of . First of all note that by the very nature of snapback, even if White a captures the stone, will recapture the White stones, so the stone will still be there. Knowing that the stone will not go away, we now note that the stone is caught in a connect-and-die: if White b, then Black c.
... and this is a capture two, recapture one where recaptures. So White has no eye here.