Matthieu Walraet: I move this from main page. The example may be confusing as it is not how actual algo works.
willemien: I don't understand the iterations. It looks like an iterated Swartz Set http://en.wikipedia.org/wiki/Schwartz_set if that is the case it should be
# Rank Club Pt MMS DC SOS-1 Rating 7 Burzo Cornel 6D RO BaMa 3 18+/b0 4-/w0 12+/b0 3-/w0 9+/b0 1-/b0 37 3 190 562 8 Simara Jan 6D CZ KaVa 3 3-/w0 23+/b0 15-/w0 10+/b0 16+/w0 4-/b0 37 2 185 523 9 Zhurakovskyj Bohdan 5D UA Rivn 3 15-/b0 22+/w0 10+/w0 4-/b0 7-/w0 18+/b0 37 2 184 432 10 Florescu Ion 6D RO Pits 3 1-/b0 13+/w0 9-/b0 8-/w0 19+/b0 17+/w0 37 1 187 561 11 Jabarin Ali 5D IL TAv 3 4-/w0 16+/b0 6-/b0 18+/w0 13+/b0 5-/w0 37 1 187 457 12 Lin Viktor 5D AT Gote 3 5-/w0 14+/b0 7-/w0 19+/w0 15+/b0 6-/b0 37 1 186 446 13 Corlan Lucian 5D RO Bucu 3 6-/w0 10-/b0 24+/w0 25+/b0 11-/w0 15+/b0 37 0 183 428 14 Serban Mihai_Valentin 4D RO Bist 4 19+/w0 12-/w0 30+/b0 5-/b0 22+/b0 16+/w0 37 0 182 349
Burzo, Simara, Zhurakovskyj, Florescu, Jabarin and Lin all defeated at least one player in the group so should not be last. Corlan and Serban have not. Corlan and Serban are therefore both removed.
# Rank Club Pt MMS DC SOS-1 Rating 7 Burzo Cornel 6D RO BaMa 3 18+/b0 4-/w0 12+/b0 3-/w0 9+/b0 1-/b0 37 3 190 562 8 Simara Jan 6D CZ KaVa 3 3-/w0 23+/b0 15-/w0 10+/b0 16+/w0 4-/b0 37 2 185 523 9 Zhurakovskyj Bohdan 5D UA Rivn 3 15-/b0 22+/w0 10+/w0 4-/b0 7-/w0 18+/b0 37 2 184 432 10 Florescu Ion 6D RO Pits 3 1-/b0 13+/w0 9-/b0 8-/w0 19+/b0 17+/w0 37 1 187 561 11 Jabarin Ali 5D IL TAv 3 4-/w0 16+/b0 6-/b0 18+/w0 13+/b0 5-/w0 37 1 187 457 12 Lin Viktor 5D AT Gote 3 5-/w0 14+/b0 7-/w0 19+/w0 15+/b0 6-/b0 37 1 186 446
Burzo, Simara, Zhurakovskyj defeated at least one player in the group so should not be last. Florescu, Jabarin and Lin have not. Florescu, Jabarin and Lin are therefore all removed.
# Rank Club Pt MMS DC SOS-1 Rating 7 Burzo Cornel 6D RO BaMa 3 18+/b0 4-/w0 12+/b0 3-/w0 9+/b0 1-/b0 37 3 190 562 8 Simara Jan 6D CZ KaVa 3 3-/w0 23+/b0 15-/w0 10+/b0 16+/w0 4-/b0 37 2 185 523 9 Zhurakovskyj Bohdan 5D UA Rivn 3 15-/b0 22+/w0 10+/w0 4-/b0 7-/w0 18+/b0 37 2 184 432
Only Burzo defeated a player in the group and is therefore the winner.
Note that this procedure does not always give a winner if A defeated B, B defeated C and C defeated B this tiebreaker ties the 3 players.
isd: No, for a 'cycle of players' (group of tied players) the one(s) with the lowest secondary tiebreaker are removed. Direct Confrontation needs a secondary tiebreaker to operate. See the 3rd and 4th points in the definition provided by Open Gotha
MatthieuWalraet: The math name for Direct Confrontation is Topological sorting http://en.wikipedia.org/wiki/Topological_sorting
Is this a Schwartz set? The definition requires that players have beaten all opponents outside the set, which is not necessarily the case.
If I correctly understand Schartz Set, in this case it should be 7, 8 and 11.
Anyway, the direct confrontation example done by isd and HermanHiddema on main page is correct. That's why I moved Willemien question here.
To me it just all looked like the swartz set but then only applied to the players inside the tied group that is concidered ( so not concidering the players outside the group)
If you apply it to all players probably all the players that you are trying to break the tie between will be removed.
To MatthieuWalraet can you explain how you get to 7 8 and 11?. (maybe i am wrong)