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captures the black stones.
If Black plays elsewhere, at captures .
For information on at another place, see Failure (Part 1)
at a is normally considered to be the mainline solution of this problem.
at b and c are pretty interesting, too.
For information on at another place, see Failure (Part 3)
at x would be a transposition to the variation in Resistance 'b'
Since after , the black chain has 5 liberties.
The only possible (other than the solution move or silly kikashi) would be at one of the x, or gets captured.
For the other , after , the black chain has 5 liberties.
If White wants to keep the black chain's liberties less than 5, White needs to play on nose points like , , and .
This turns into a ladder that doesn't work.