: Re: is notcher code complete?
(2009-11-05 13:27) [#6525]
These are, in order: 311NN, 211NS, 312NN, 212NS. In both diagrams 2 and 4, you've put a square on one stone too many, ie:
The stone makes that the right side is strong (S) in the code. If it were empty, it would be neutral (N), if it were white it would be weak (W). So this is 211NS
The point marked a is just an outside liberty.