# Under The Stones Problem 7 / Attempts

Black is (almost) alive (?)

After , there seem to be several continuations; in the most direct, and capture five black stones...

Black is alive in a simple way

unkx80: The in the above diagram is dubious. here is very simple and direct. Then a and b are miai.

Well, excuse me! You are right, of course. My doesn't work because leads to ko (and costs Black four extra stones)!

Continuation (of first diagram)

After , if White captures Black's square with and , forms two eyes. Note that White cannot subsequently play at a!

Continuation problem

unkx80: Although White cannot play at a, there is also the move at to consider. I leave it to you to figure what is the result.

OK! Black's shortage of liberties comes into play, and Black must play at A, resulting in a ko fight!

Black can also take White's stone, or play at B, but the ko can't be avoided.

unkx80: No... Black still can live unconditionally. Refer to some of the other solution diagrams to figure out how.

10 at 7, 4 at 1
1 Kills. I referred to another solution :P

Kuolema: I can't see how can black live unconditionally, any way I look at it, it leads to a ko. (Unless black wants to kill himself)

unkx80: Eh... my mistake. Sorry. =P

Black is alive ?????

Black is alive ?????

@ , killing.

Black is alive

Black is alive

Black is alive

@ , living.

Under The Stones Problem 7 / Attempts last edited by Unkx80 on March 19, 2008 - 19:37
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