Gokyo Shumyo, Section 1, Problem 87 / Solution
variations: unkx80 and Dieter
Solution
![[Diagram]](../../diagrams/14/7ca81f8eaa8a723849f57c667f6cbdc4.png)
Main line
After
, White can't play at a because of the snapback.
![[Diagram]](../../diagrams/23/83ebca8745cebbdf42a0f5ca5e8bd0a7.png)
Continuation
So Black captures and can connect at
if White ataris at
.
![[Diagram]](../../diagrams/10/8ce5f0d1483f1b220e2add1b1934b679.png)
Variation 1
If White connects at
,
and
captures the three stones including
(White a, Black b).
![[Diagram]](../../diagrams/10/8bede115d770b1b845afbe3e3fc5ceed.png)
Variation 2
White can not play this way because the marked black stone assures the second eye at the circled point.
Failures
![[Diagram]](../../diagrams/30/7cced8d98daa95ae3e818e31199689a7.png)
Failure at 7
The order of play is important here. If Black tries to get a stone at
first, then gives atari, White's shortage of liberties has vanished. She plays
to make miai of cutting at a or saving the cutting stones at b.
![[Diagram]](../../diagrams/27/e43335df3c11ec3fc26379fab01a10bb.png)
Failure at 7 (ii)
Here, White simply connects and has one liberty more than the 4 stones in atari.