White forces with and
(the order of which is important) then with
threatens to make a second eye: Black can't make it false at the marked point, because White will push through at a and take two stones. So he plays
, upon which White connects at
.
Now at first sight, the shape is one of a dead group: a three point big eye, and a false eye at the top.
Surprisingly enough, White captures with and
, making miai of replaying under the
stones!! For reference ...
There are many opportunities for White to go wrong. Let's analyze some:
(To be continued - please contribute if you want.)
At , if White plays
instead of a, Black answers at
to keep White down to one eye. If next White captures two stones at a, he throws in at
. White should capture simultaneously to make miai of Black's answers. The order of a and
(
and White 11) is important.
If White plays at
here (instead of connecting at
) Black captures at
and the miai are destroyed.
In the main line, White hasn't yet exchanged b for , so when she plays atari at
, and
captures,
makes miai of a and b.
If the order of and
didn't matter, then either one of the answers would be different.
But Black can answer at
, then
at
as in this diagram. Next, White comes one move too late: after
, a and b are miai.
Finally, what if White ataris from the other side ?
I thought, well, now Black can destroy the eye with , since the aji now works against White:
is atari. But ...