is the only move. The only correct answer for Black is at
. White's correct answer is at
, and note that White must capture the black stone at
, resulting in ten thousand year ko.
This dies easily.
Death in bulky five. If Black continues with atari at a, White simply connects at .
After , a and b are miai.
Resistance at is useless here.
The black group dies as well: a and b are miai.
If White plays at here, Black lives in seki: either he makes seki at a, or if White plays there, Black can capture her bent four in timely fashion.
With the clamp at , Black lives.
If White plays at a to prevent a seki, then Black plays at b to form a bent four live group.
After (oshitsubushi), White is short of liberties and cannot play at
to form a bulky five, so Black lives.
White 4 here doesn't work... after , White is caught in a connect-and-die.
Same fate here if White chooses to take the ko at instead.
Mistake upon mistake upon mistake
In KanazawaProblem20 was already a mistake. White's hane - as we now know - is another one and then
is yet another one.
makes miai of a and b: b would enable White to almost fill Black's eye space with a bulky five and White a would make an eye inside Black's group. If Black rushes to capture White's stones, he's left with a farmer's hat space inside his group.
KarlKnechtel (~14k)
Can't Black also live by escaping with a monkey jump in this case?
No escape. --unkx80
Contributors