Please verify --Dieter
1. No outside liberties
In addition, we will assume the marked stones, so as to give Black no escape routes to the outside. In this case, White can kill by playing the obvious placement at a.
We will consider the following answers by Black: the hane of a, the descent of b and the perhaps less obvious placement of c.
After , a and b are miai for the kill:
Black will eventually be forced to fill at a, after which his eyespace is almost filled with bent three. If White omits , Black gets at least seki by playing there
Less intuitive perhaps is this variation. makes an eye in the stomach. White will eventually be able to fill the inside liberties. If Black does so, his eyespace will become almost filled with a farmer's hat killing shape.
In this variation, the outside liberties are important. Black puts up resistance, but White makes an eye in the stomach. She counts the inside liberties for a total of three. Black has only two outside liberties and falls short.
If here
falsens the eye.[1]
If here,
makes miai of a and b to either reduce Black's eyespace to three in a row or make an eye in the stomach with a farmer's hat shape.
The cunning placement of reverts to the above.
is again the key point.
If White connects with ,
makes it a seki.
If here, Black makes it ko.
again leads to seki.
[1] Comments:
Nope... after , a and 4 are miai.
2. Outside liberties
If Black has an extra liberty, this variation doesn't work anymore. Black lives through capturing a bent four.
Same thing
If here,
now sets up a ko.
The placement too works.
As with this seki.
This one looks alive. Any attempts ?
Matthew Woodcraft: I can't see a way to kill.
Charles Matthews I believe ko is the correct answer.
unkx80: How about and
?
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