Beginner Exercise 29 Solution
Difficulty: Beginner
Keywords: Problem
![[Diagram]](../../diagrams/31/399ad9d5cfa0c09b7989ebf80a0bbda2.png) | Solution |
at or is shortage of liberties, and at (or elsewhere taking a black liberty) by the same (connect-and-die).
captures two stones, leaving equal number of liberties with Black to move...
![[Diagram]](../../diagrams/25/ef4117287977c65d162e7dde628a1548.png) | Solution |
And wins the capturing race by one move.
is a must.
![[Diagram]](../../diagrams/5/7dc511fe920e069e10ca52368066e92a.png) | Alternative |
Black can be even more direct - after the stones are in a snapback.
![[Diagram]](../../diagrams/21/6653495313460a8e4ac264606e9a544c.png) | No snapback but White still loses |
Or if White defends the snapback, puts the white group into atari.
![[Diagram]](../../diagrams/3/bf5c4bc98e6eb51808300afd78f2c4d0.png) | Failure. |
The atari at is wrong...
![[Diagram]](../../diagrams/10/03cb720e94b440d49ccd1715b2c5deae.png) | Failure, continued |
...when White plays the hane at , Black is stuck. If Black pushes at a, he is in self-atari.
![[Diagram]](../../diagrams/49/c62c7e81d3cc2b2a62960d396eed35a6.png) | Black to live. |
The above solution(s) are incorrect. The vital point is . Once is played, White must play at to survive. Black then plays at . White captures with to prevent Black from capturing it's group. At this point Black must play at . is not in atari so there is no need to solidify with 'a', for if Black did play at 'a', White would respond with 'b'. If Black plays at , White will be captured and Black can live.
The statement above is wrong. After white has an eye and black does not. White can even play tenuki. If now black plays a white plays b and vice versa. This situation is called me-ari-me-nashi. Hans
Karl Knechtel, lavalyn, Scartol
This is a copy of the living page
"Beginner Exercise 29 Solution" at
Sensei's Library.
2004 the Authors, published under the OpenContent License V1.0.
|