The solution is: White is alive -- so both sides should tenuki.
After the previous diagram, 'a' and 'b' are miai. If Black A, then White B; and if Black B, then White A. In both cases White will have enough liberties to capture the internal Black group.
If Black tries to take a more symmetric point, then is good enough. Soon, A and B become miai for White.
Notably, there exists a similar common corner shape as shown below.
Black 1 is a wrong attack leading to the starting position for Xuanxuan Qijing Problem 3. White is alive after this sequence.