It is of course completely possible that the readers are mistaken about the 'mistakes', so please add if you know more!
Thanks to Bozulich for this great book. The lack of explanations in the book really motivates one to look further and work on the problems in depth.
--Skelley
Table of contents |
The solution is correct, but the location of the 'b' annotation is wrong, it should be one line lower at the 1-3 point.
The solution text says: If White plays the diagonal move..., but it should be: If Black plays the diagonal move....
The solution says: ...a dead four-point eye space., but it should be: ...a dead five-point eye space.
takes back at
.
Or Black can make independent life, also in gote. Later -
is sente.
Problem 300 is described as "Black to kill" and is in the section labelled "One-move problems - Black to kill" when it is actually Black to live. Note, the second printing (from June 2006) has this correctly labelled as "Black to live".
"Black peeps at . If White a, Black b. If White b, Black c also kills White."
The c is omitted in the diagram.
Note: The c can be either of the two points.
The solution says "Black connects with 1. If white blocks at A, Black makes a placement at B."
A placement at C also works.
The solution says "Black 1 links up with his three stones below. White has only one eye."
Actually, white has no eyes; both the 1-2 point and the 2-3 point are false eyes.
The text says "Black creates a dead eye space. If White a, Black b. If White c, Black d."
However, there are no c and d on the diagram.
It is possible that the intended sentence is "If White b, Black a."
This has been corrected in the 2006 edition.
Solution text says "If Black 1 at 2, White will descend to 1 and the black stones are short of liberties." Actually, the black stones are not short of liberties, but Black is dead anyway.
Solution says "...If White 2, Black draws back to 3 and he is alive."
Should say "...If White 2, Black at 3 or a lives."
From the first printing dated February 2002.
The solution diagram shows how Black kills White. This problem is misplaced and belongs in part six of the book which contains five move Black to Kill problems.
The given solution is correct. However, the solution text then says If Black 1 at 3, White 1 leads to a ko. This is wrong, there is no ko; if Black 1 at 3, White 1 kills.
Actually, Black can just connect his stones at a or b since White cannot make a false eye on the left. This way he does not have to sacrifice two stones to live.
Obviously, the stone should be removed from this problem for the intended solution to be the best solution.
Instead of , White can extend at
in Diagram 1, and Black does not have enough liberties to play at
, and so must capture the four white stones...
Now White can play back under the stones to form a 10,000 year ko. The book states none of the "Black to live" solutions involve ko...
/Problem 752 - Mannenko Discussion
I believe, that the result is seki, not two eyes for black.
Black is not unconditionally alive. (Page iv says that unconditional life is intended in all "Black to live" problems.)
The solution given in the book:
And now we have an approach ko for white, which, if won, kills black.
( at
is a direct ko.)
The problem says "Black to kill", but White can live with this sequence.
The solution given is:
Black easily lives with 1. Black A also lives, but with a double ko.
However, there is another solution equally as good as 1. The solution should look like this:
Black easily lives with 1 or B. Black A also lives, but with a double ko.
Solution diagram gives as the solution. However, Black a works too.
Solution diagram gives as the solution. However, Black a also works.
Solution diagram gives as the solution. Black a also kills. However, the book solution
is better than a, because if black needs to actually remove the white stones,
avoids any possibility of ko in the corner.
5 at a or b also works, but these are slightly inferior to the book solution since they do not kill white as quickly.
5 at a also works, but is slightly inferior to the book solution.
5 at a also works, but is slightly inferior to the book solution.
The solution in the book shows this sequence as a solution. However, having to directly hit the vital point at
is also a solution (think incomplete bulky five).