Cut
Dieter: First idea: cut
Var 2.
Var3.
I think the order of and is what unkx80 is talking about. Hm, maybe not on second thought.
unkx80: Yes, you are right, living by the method discussed in eye by exhaustion. =)
Var 4.
Var 5.
Failure 1 (4 at 2)
Failure 2.
Failure 2a
=
Failure 2b
Referenced byRTGProblem11