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Maximum Number Of Liberties In A Dead Chain
Keywords: MiddleGame, EndGame
Maximum number of liberties in a dead chain
This should be taken with humour, not as a refutation of the "Five liberties for tactical stability" proverb. It is also a challenge as the MaximumNumberOfLiveGroups page. Can anyone find a higher number of liberties for a dead chain on a 19x19 board? (If someone doubts black is dead: The only eyes black can do require two miai moves as a + a or b + b. Should black play at any of the a, white must play at the other. The same for b and the same for any other corners. Also, if black plays at c, d is the right answer (or in reverse order). There is nothing black can do to make an eye except z (if in sente) and that single eye is not enough for living.) Jacques Basaldúa
Rakshasa's suggestion:
unkx80: I can't count, so someone please verify my claim. Note the big eye has 17 - 2 = 15 liberties.
unkx80's solution has 148 liberties (still better than mine). Rakshasa's is the best and the simplest. Jacques. Tom: I think the problem here is the ambiguity described in the Liberty page. I'm going to try an example that may not be entirely original.
One more at least.
How do you count 155 liberties for that? I don't. I count 155 liberties for Tom's solution. Then, I try to explain why black is dead and white is alive even if she has only one eye. The answer: White can kill black as shown in my diagram (which is Tom's solution after the potential moves white could do to kill black.) Sorry if I didn't explain it ok. This is a copy of the living page "Maximum Number Of Liberties In A Dead Chain" at Sensei's Library. ![]() |