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No Pass Go Problem 1 / Solution
Sub-page of NoPassGoProblem1
White to play and win.
Analysis: The top left is worth 3 moves and the top right is worth 2^ (2 plus up). Subtract 2 for the group tax and the Black group is worth 3^. The bottom left is worth -1 (one move for White), OC, and the bottom right is worth -4* (4 star). Add 2 for the group tax and the White group is worth -3*. The sum is 3^ - 3* = ^*. (The negative of * is *, so subtracting it is like adding it.) Solution: There is more than one solution, but canonical play is for White to move from 2^ to 2* in the top right. The result is * - * = 0, which is a second player win.
Now the miai is obvious. Black will have to fill his second eye before White.
This is a copy of the living page "No Pass Go Problem 1 / Solution" at Sensei's Library. ![]() |