Kanazawa Solution 55
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Keywords: Life & Death, Problem
![[Diagram]](../../diagrams/43/63cc21ad220e96fba8bbd9d9e6955481.png) | Main line |
White forces with and (the order of which is important) then with threatens to make a second eye: Black can't make it false at the marked point, because White will push through at a and take two stones. So he plays , upon which White connects at .
Now at first sight, the shape is one of a dead group: a three point big eye, and a false eye at the top.
![[Diagram]](../../diagrams/9/7bb2be520fe839497bba61e59facc4d8.png) | Continuation |
Surprisingly enough, White captures with and , making miai of replaying under the stones!! For reference ...
![[Diagram]](../../diagrams/34/36e4648364c64e37a609aeaefc6687c7.png) | Continuation |
When Black throws in, White makes two eyes at , sacrificing three stones at the top.
There are many opportunities for White to go wrong. Let's analyze some:
(To be continued - please contribute if you want.)
![[Diagram]](../../diagrams/16/47d2e1af83d275cc3da890ccca6940df.png) | Failure at 9 |
At , if White plays instead of a, Black answers at to keep White down to one eye. If next White captures two stones at a, he throws in at . White should capture simultaneously to make miai of Black's answers. The order of a and ( and White 11) is important.
![[Diagram]](../../diagrams/29/efca5b45c60172376958546283af9e0d.png) | Failure at 7 |
If White plays at here (instead of connecting at ) Black captures at and the miai are destroyed.
![[Diagram]](../../diagrams/2/24a6f3d12362832cccfb0fb702e90f5f.png) | Failure at 5 |
White has now one big eye almost filled with three stones. There is no threat in a.
![[Diagram]](../../diagrams/15/7c16e1a677e525acb9df7e15ad0807a4.png) | Failure at 3 |
If White changes the order of and , Black can answer at and make it ko with .
![[Diagram]](../../diagrams/26/ab7c99438fee8f311cd725d14333530d.png) | Order of 3 and 5 - variation at 4 |
In the main line, White hasn't yet exchanged b for , so when she plays atari at , and captures, makes miai of a and b.
If the order of and didn't matter, then either one of the answers would be different.
![[Diagram]](../../diagrams/49/41d65c301ddf95c9b592610dd585021b.png) | Variation - order of 1 and 3 |
Suppose w3 is not answered at a; then makes life.
![[Diagram]](../../diagrams/52/4d5d6c1c1c768a55c579a488255f4653.png) | Variation - order of 1 and 3 |
But Black can answer at , then at as in this diagram. Next, White comes one move too late: after , a and b are miai.
Finally, what if White ataris from the other side ?
![[Diagram]](../../diagrams/31/c1dc182a68aca3a3c3db5ad8c9576870.png) | Variation at 1 |
I thought, well, now Black can destroy the eye with , since the aji now works against White: is atari. But ...
![[Diagram]](../../diagrams/1/5c4e9807f244fc01813793debf553ee1.png) | Variation at 1 |
... the capture makes miai of a and b. So ?
Problem 56
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This is a copy of the living page
"Kanazawa Solution 55" at
Sensei's Library.
2004 the Authors, published under the OpenContent License V1.0.
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