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Kanazawa Solution Three
Path: KanazawaSolutions · Prev: KanazawaSolutionTwo · Next: KanazawaSolutionFour
Keywords: Problem
Authors:
Main line: HashimotoUtaro 9p
After 1, making an eye at the circled point, a and b are miai for life.
After 3, Black has real eyes at the circled points.
It seems as if White makes the eye false, but the capture of three stones with 5 results in a real eye.
Even if white throws in at 6, Black lives with 7.
If White captures at 2, Black 3 makes a second eye. If Black doesn't respond, White a kills the group.
The other 1-2 point is again not successful. With 2, Black is left on the spot. Even if allowed to play two moves in a row, he can't live any more.
When Black plays 1 here, White can choose between a and b to kill Black. Someone with an opinion which is the better ?
Also wrong is Black 1 here. White 2 and 4 leave a and b as miai for the kill.
Making the eye as large as possible, with Black 1 here, seems to be correct as well, but it is not the solution from the book. After White 2, Black 3 follows, and Black lives as shown. White 3 is followed by Black 2, White a, Black 7. White 7 is answered by Black 3. White 4, Black 7. White 5, Black 4.
If Black 1 is a mistake, then it must be because White can next play at 2. If Black now plays 3, White 4 kills the entire black group. But ...
... when Black throws in at 3, White fails. The authors of the variations shown here, have not yet found the reason why 1 in the main line is preferred to 1 here.
I received the following suggestion. White 2 is sente against Black 1. If Black doesn't answer ...
4 at 1. The result is ko.
White's descent here is not sente.
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