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BQM 17
This is the position after move 84 in the second game of the 46th Honinbo, with Cho Chikun holding the white and Kobayashi Koichi the black stones. The action is in the lower right part of the goban, and Cho is trying to make life for his white group there. This is the key sequence of the game (which was won by Kobayashi, by the way). The comment I struggle with says that connecting at Black 'a' is not good.
This is what White wants: he plays degiri with 2 and 4.
This is the continuation of the Diagram. The comment says that White creates eye shape following this sequence. If Black then plays 'a', White makes his second eye with White 'b', Black 'c', White 'd'. It says that Black can't counter with 'c' at 'd' because of shortage of liberties... and I don't see that! This may be a case of simple reading blindness (lecturopia? vulgaris), so it's probably not too hard for some sensei out there to enlighten me a little. --Stefan Perhaps just to deviate from your question, instead of white 'b', black 'c', white 'd', why not just play white 'd' to secure the second eye? --unkx80 Because then 'b' would be B sente - a 1 point unconditional loss is unbearable in a pro game. I think the real answer lies in the ko fight resulting after B 'd' and W pushes through.. It looks to me like B cannot win it, so he has to submit and connect when W plays 'b'. --deft 1k*?
Andre Engels: Here is what i think is meant: After black 4, white 5 gives atari, then white 7 starts a fight. If white next wins the ko at 8, black's 8 stones (the marked 5 plus 2-4-6) will be captured. I assume black is considered unable to win this ko, and thus the cut at 4 does not work. This is a copy of the living page "BQM 17" at Sensei's Library. (C) the Authors, published under the OpenContent License V1.0. |